refactor: 删除find_user_by_oidc_sub中未使用的raw username分支,避免误导
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@ -491,11 +491,6 @@ async def find_user_by_oidc_sub(db, sub: str) -> User | None:
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logger.warning(f"Multiple legacy OIDC users matched for sub={sub}, use earliest id={legacy_users[0].id}")
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logger.warning(f"Multiple legacy OIDC users matched for sub={sub}, use earliest id={legacy_users[0].id}")
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return legacy_users[0]
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return legacy_users[0]
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# 方法3: 如果启用了 use_raw_username,尝试通过 user_id 的原始值找到用户(需要先从用户信息中获取 username)
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if oidc_config.use_raw_username:
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# 注意:这里无法直接从 sub 获取 username,需要在调用处处理
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pass
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return None
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return None
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